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Neco 2017 Physics Obj And Theory Answers – May/June Expo

By | On July 9, 2017 (4 months ago)

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2017 NECO PHYSICS ANSWERS FROM EXAMCROWN.COM


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PHYSICS OBJ

1-10 CEABCBAABB

11-20 DCCBCBCCAE

21-30 BECDDBEDDE

31-40 DBAEADBABA

41-50 CBDCBBBDCB

51-60 CEDDCBAEAA

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THEORY PART I

ANSWERS 6 QUESTION

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(1a)

i)Propellant 

ii)Nozzle 


(1aii)

i)Used for communication 

ii)Used to access geographical dispersed terrains and even topography that characterise the nation’s landscape 


(1b)

Given:

Object distance for eyepiece=3.0cm

Final image distance V =? 

Focal length of eyepiece f=5.0cm

Using mirror / lens formular


1/f = 1/u    1/v

1/5= 1/3   1/v

Multiplying through with 15v 

3v = 5v   15

3v – 5v = 15

-2v = 15

V =  – 15/2

V= – 7.5cm


The final image is virtual and 7.5cm from the eyepiece on the same side of the eyepiece as the object

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(4a)

The specific latent heat of vaporization of a substance is the quantity of heat required to change a unit mass of the substance from liquid to vapour without change of temperature 


(4b)

Kinetic energy is that possessed by a body due to its motion.  While potential energy is that possessed by a body due to its height or state

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(5a)

i) solar

ii) wind


(5b)

Given:

M1=15kg,  U1 =10m/s ,  V  =? 

M2 = 5kg,  U2 =0 m/s


Using

M1V1   M2V2 = V(M1   M2)

15(10)   5(0)  V(15   5)

150 = 20V

==>20V = 150

V = 150 / 20

V= 7. 5m/s

Common velocity  =7.5m/s

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(6a)

A line or surface in the path of an advancing wave on which all particles are vibrating in phase is called wave front


(6b)

(i)plane wavefront

(ii)spherical or  circular wavefront

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(7)

Pupil: Regulate the amount of light entering the eye


 Shutter: Admits or shuts off light from the film of the camera

 

Screen: Used to focus light from a near object in front of the pinhole camera

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(9a)

i) Over charging(for secondary cell) ii)self discharge (for primary cell) 


(9b)

Self discharge:A primary cell lose a considerable percentage of their charge when stored at room temperature. This is due to non-current producing “side” chemical reaction that occur within the cell even when no load is applied


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(10)

(i)Fusion is more easily achieved with lightest elements such as hydrogen 


(ii) The raw materials required for fusion are more cheaply and readily available 


(iii) Fusion process produce less dangerous  by-products



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PART II 

ANSWER 4 QUESTIONS

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12ai) Newton’s second law of motion states that the rate of change of momentum is proportional to the impressed fotvr and takes place in the direction of the force


12aii)- The motion of the strings in a musical instrument eg. Guitar

– The motion of the balance wheel of a watch


12bi) Resultant force is that single force which acting alone will have the same effect in magnitude and direction as two or more forces acting together


12bii) Equilbrum force is that single force which will balance all the other forces taken together. It is equal in magnitude buy opposite in direction to the resultant force


12ci)

Resultant force  F =√4^2 + 3^2

F =√16 + 9

F =√25

F=5N


2cii)

Using F =  m(v –  u) / t


5= 5.5 (v – 2) / (5 × 60) 

=5 × 60×5 = 5.5(V-2)

5.5(V –  2) = 1500

V – 2 = 272.7

V=272.7 + 2

V=274.7m/s


Final velocity of body is = 274.7m/s

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13ai)- Solar energy  is for providing a cheap and clean source of hot water supply.

– Solar energy provides electricity supply


13aii)-Renewable energy are  those that can be replaced as they are used up. They can be continually replenished as they are exploited and utilized while Non-Renewable energy are those that cannot be replenished as they are used up

-Examples of renewable energy are Solar energy, wind energy, Biomass and Bio feuls while examples of Non renewable energy are Coal and wood, Fossil fuel, Petroleum and Natural gas, Nuclear energy


13b) The principle of conservation of linear momentum us also utilized in the propulsion of jet aircraft. Gases are burnt within the combustion chambers of the engine. As jets of hot gases are expelled downwards through the tail nozzle at very high speeds from the aircraft, an equal and opposite momentum is given to the rocket or aircraft which then moves



13c)

Given Mass = 0.2kg

H = 4200J

θ1 = 100degreeC

θ2 = ?

Using

Heat lost = Mw Cw (θ1 – θ2)

4200 = 0.2 x 4200 (100 – θ2)

100 – θ2 = 4200/0.2×4200

100 – θ2 = 5

θ2 = 100 – 5

θ2 = 95

I.e The Final temperature = 95 °C


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(14a)

(I) A transverse wave is one which travels perpendicularly to the direction of the vibration producing the wave.

(II) 

– Light Wave do not need a material medium for preparation, but sound wave does

– Light wave cannot be plane polarised but sound wave can



(14b)

Given Y= 4sin (100×22/7xt/2 + 0.5x)

Comparing with

Y = A sin (2xPIxft + 2pi/pi x) Note : {the PI is the 22/7}


(I) 2 x 3.142/0.5 = 12.56cm

Hence Wave length is 12.56

 

(II) Also 1000PI/wave length = 2PI F

= 1000PI/12.56 = 500/12.56

= 39.8Hz


(III) 

Speed (v) = F x Wave length

= V F x Wave Length

V = 500/12.56 x 12.56

= 500cm/s

Conversation to M = 500/100

= 5m/s


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(15a)

Coulomb’s law state that magnitude of the electrostatic force of attraction between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance  between them


(15bi)

DIAGRAM

———-|I——— R1

———-|I———R2

———-|I———R3

–<—–|I(v)———-



(15bii)

Let equivalent resistance be  R

1/R  = 1/R1 + 1/R2 + 1/R3

I/R = R2R3 + R1R3 + R1R2 / R1R2R3

R= R1R2R3 / R1R2+R2R3+R1R3


(15c)


GIVEN!

200Ω C =4mf   f=50h2   π =3.14

Impedance  Z =√R^2 + (1/2Ω + c) ^2

Z =√200^2 + (1/2×3.145×50×4×10^-6)^2

Z=√200^2  + 796.178^2

Z=√40000 + 633900

Z=√673900

Z=821Ω


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COMPLETED FROM STUDENTCLUB.COM.NG

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